Undergrad Unitary Matrix Representation for SU(2) Group: Derivation and Verification

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The matrix representation for the SU(2) group is defined as U = [[α, -β*], [β, α*]], where α and β are complex numbers satisfying |α|² + |β|² = 1. The discussion explores whether any complex 2x2 matrix with unit determinant is necessarily unitary, highlighting a misunderstanding in the argument presented. It clarifies that while the determinant condition is necessary, it does not imply that U equals U†, as det(A) = det(B) does not mean A = B. The most general form of a complex 2x2 matrix with unit determinant is given by U = [[a, b], [c, d]] with ad - bc = 1, which is broader than just the SU(2) representation.
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The matrix representation ##U## for the group ##SU(2)## is given by

##U = \begin{bmatrix}
\alpha & -\beta^{*} \\
\beta & \alpha^{*} \\
\end{bmatrix}##

where ##\alpha## and ##\beta## are complex numbers and ##|\alpha|^{2}+|\beta|^{2}=1##.

This can be derived using the unitary of ##U## and the fact that ##\text{det}\ U=1##.Is any complex ##2\times 2## matrix with unit determinant necessarily unitary?Consider the following argument:

##\text{det}\ (U) = 1##
##(\text{det}\ U)(\text{det}\ U) = 1##
##(\text{det}\ U^{\dagger})(\text{det}\ U) = 1##
##\text{det}\ (U^{\dagger}U) = 1##
##\text{det}\ (U^{\dagger}U) = \text{det}\ (U)##
##U^{\dagger}U = U##
##U^{\dagger}= 1##

Where's my mistake in this argument?
 
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##\det(A) = \det(B)## does not imply ##A=B##.
 
Thanks!

I was wondering what is the most general form of the complex ##2 \times 2 ## matrix with unit determinant.

My first hunch was that it is the ##2\times 2## matrix representation of the ##SU(2)## group, but then, a complex ##2 \times 2 ## matrix with unit determinant is not necessarily ##SU(2)##.

Can you help me with finding the most general form of the complex ##2 \times 2 ## matrix with unit determinant?
 
failexam said:
Can you help me with finding the most general form of the complex 2×22×22 \times 2 matrix with unit determinant?
I don't think there's anything special about it. As far as I know, it's just:
$$U= \begin{bmatrix} a & b \\ c & d \\ \end{bmatrix}$$
where ##a,b,c,d \in \mathbb{C}## and ##ad-bc = 1##.
 
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