Unusual question regarding torque

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two equivalent mases, m, are placed on two corners of a triangle with 3 sides each of length a (i.e an equilateral traingle). The third corner is fixed (not free to move).
The triangle orginally starts with one side perfectly vertical. Gravity acts downward intially, calculate the accelerations of the masses right after the system is let go .
 

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Find torque and moment of inertia around the fixed point

Use torque = moment of inertioa X rotational acceleration