Using Impulse-Momentum to Find Time of Falling Object

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The discussion focuses on applying the impulse-momentum theorem to determine the time it takes for a falling object to accelerate from a speed of 5.50 m/s to 9.00 m/s. The user initially calculated a time of 3.5 seconds but later corrected their approach. Using the formula vf = vi + at and substituting the values, they found the correct time to be approximately 0.357 seconds. The calculations involved understanding momentum and impulse, emphasizing the relationship between force, mass, and acceleration due to gravity. The thread concludes with a successful resolution of the problem.
jheld
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Homework Statement


Use the impulse-momentum theorem to find how long a falling object takes to increase its speed from 5.50 to 9.00 .


Homework Equations


deltaP = impulse
P = momentum (m*v)
impulse = J (integral from ti to tf)

The Attempt at a Solution


3.5 seconds, though, I knew before that it was incorrect.
 
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well, I got it, now :)
vf = vi + at
-9 = -5.5 -9.8t
solve for t = .357 seconds
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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