Using Mathematical Induction to Prove a Summation Formula

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Discussion Overview

The discussion revolves around using mathematical induction to prove a summation formula involving a series of terms multiplied by powers of 6. The focus is on the transition from the statement for \( S_k \) to \( S_{k+1} \) and the algebraic manipulation required to establish the inductive step.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant presents the initial statement \( S_k: 5\cdot 6 + 5\cdot 6^2 + 5\cdot 6^3 + ... + 5\cdot 6^k = 6(6^k - 1) \) and seeks guidance on proving \( S_{k+1} \).
  • Another participant corrects the notation for the inductive step, indicating that the right side should be \( 6(6^{k+1} - 1) \) and asks if the original poster can derive this algebraically.
  • Subsequent posts show attempts to manipulate the right-hand side (RHS) expression, with one participant providing an intermediate form of the RHS as \( 6^{k+1} - 6 + 5\cdot 6^{k+1} \).
  • Further contributions involve combining like terms and factoring, leading to a final expression of \( 6(6^{k+1} - 1) \), which aligns with the corrected form suggested earlier.

Areas of Agreement / Disagreement

Participants appear to agree on the steps needed to manipulate the expression, but there is no explicit consensus on the overall proof structure or any potential errors in earlier steps.

Contextual Notes

There are indications of missing assumptions regarding the initial conditions for the induction proof, and the discussion does not clarify whether all algebraic steps are fully resolved.

ineedhelpnow
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$S_k:5\cdot 6 +5\cdot 6^2+5\cdot 6^3+ ...+5\cdot 6^k=6(6^k-1)$$S_k:5\cdot 6 +5\cdot 6^2+5\cdot 6^3+ ...+5\cdot 6^k+ 5\cdot 6^{k+1}=6(6^k-1)+5\cdot 6^{k+1}$

what do i do now? to prove $S_{k+1}$
 
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The second statement should be labeled as $S_{k+1}$ and you want the right side to be:

$$6\left(6^{k+1}-1\right)$$

Can you get from what you have to there algebraically?

By the way, I am going to move this thread to the Pre-Calculus subforum and retitle it to remove the abbreviation.
 
i don't know how to get there
 
here's all I've done so far:

RHS
$6^{k+1}-6+5\cdot 6^{k+1}$
 
ineedhelpnow said:
here's all I've done so far:

RHS
$6^{k+1}-6+5\cdot 6^{k+1}$

Okay, combine like terms and then factor...
 
$6^{k+1}-6+5\cdot 6^{k+1}$

$[6^{k+1}+5\cdot 6^{k+1}-6$

$[6^{k+1}(1+5)]-6$

$6[6^k(6)-1]$

$6(6^{k+1}-1)$
 
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