Variation of Hubble constant in cosmological time

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
9 replies · 4K views
spaghetti3451
Messages
1,311
Reaction score
31
Is the Hubble constant decreasing over cosmological timescales?
 
Astronomy news on Phys.org
Yes:
H evolution.png
 
Why did the Hubble constant tend to infinity in the early universe?
 
Mostly for the same reason that f(x)=1/x goes to infinity as x goes to 0. Remember that H is the proportionality factor between recessional velocities and distances: H=V/D. As the distances between receding objects decrease to 0, H goes to infinity.
An additional effect comes from V being larger in the past, but that's secondary.
 
  • Like
Likes   Reactions: spaghetti3451
The relation

$$H = 1.67 \sqrt{g_{*}} \frac{T^{2}}{M_{P}}$$

is valid during the radiation-dominated epoch. Is it valid during the inflationary epoch?
 
spaghetti3451 said:
The relation

$$H = 1.67 \sqrt{g_{*}} \frac{T^{2}}{M_{P}}$$

is valid during the radiation-dominated epoch. Is it valid during the inflationary epoch?
No.
 
  • Like
Likes   Reactions: spaghetti3451
What would be the correct relation for the Hubble parameter in the inflationary epoch?
 
That would depend on the equation of state for whatever is driving inflation. If what drives inflation behaves as a cosmological constant, then the Hubble parameter would be constant during inflation.
 
  • Like
Likes   Reactions: spaghetti3451
Would you share a review article which discusses this in more detail?