Greetings all!(adsbygoogle = window.adsbygoogle || []).push({});

So,

[tex]\nabla X \vec{F}[/tex] is confusing me.

I understand that it can be used to tell whether a force is conservative in that, if the curl is 0 then the work done all all paths are the same... that's fine.

However,

I was looking at it, for example, in the context of the gravitational field. When drawing it out, one can see that the curl is indeed 0, and I've been told that it is proven by [tex]\nabla X \vec{F}[/tex], BUT from what I understand, and from what I've been told, the operator [tex] \nabla [/tex] has no direction, and thereby not a vector....

yet used in a vector product?

How can it even by setup in the first place if the operator isn't a vector?

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Vector product - operator's a vector?

Loading...

Similar Threads - Vector product operator's | Date |
---|---|

I Method for solving gradient of a vector | Jan 3, 2018 |

B Solving a differential equation with a unit vector in it | Nov 25, 2017 |

I Partial Vector Derivative | Oct 15, 2017 |

I Constructing left invariant vector fields on SO(3) | Apr 3, 2017 |

Using the product rule for the partial derivative of a vector function | Nov 24, 2013 |

**Physics Forums - The Fusion of Science and Community**