- #1

bernhard.rothenstein

- 991

- 1

U(t(r)-t(e))=Vt(r) (1)

where from

t(r)=Ut(e)/(U-V) (2)

Replacing the MG with a source of light we obtain

t(r)=ct(e)/c-V).

We could follow scenarios which lead to an expression containing the terms U+V and c+V. Are U+V, U-V, c+V and c-V the result of a velocity addition?