What Velocity Does the Sled Reach After 5 Seconds?

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The discussion focuses on solving a physics problem involving Newton's Laws of motion, specifically calculating the sled's acceleration, velocity after 5 seconds, and distance traveled. The boy exerts a force of 300 N while facing a frictional resistance of 200 N, resulting in a net force of 100 N. Given the combined mass of the sister and sled is 50 kg, the acceleration can be calculated using F = ma. The initial velocity is considered to be 0, allowing the final velocity to represent the increase in velocity over the 5 seconds. The conversation emphasizes the importance of understanding the relevant formulas and how to apply them to find the answers.
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OK I'm stuk on a physics question involving Newton's Laws of motion.

Question:

Boy gives his sister ride on sled by exerting force of 300 N[E].
Frictional resistance amounts to 200 N. If sister and sled have combined mass of 50 kg, and if boy starts from rest and pushes for 5 sec., find:

a) the sled's acceleration
b) velocity attained by sled in 5 sec.
c) distance traveled by sled in 5 sec.


PLZ try to help and show step by step solutions

Reply ASAP thanx:smile:
 
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It's not the policy here to do peoples homewrok, but I'll give you the relevant formulae:

F = ma, v = u + at, s = ½(u + v)t

F is force, m is mass, a is acceleration ,v is final velocity, u is intial velocity, s is displacemnet and t is time.
 
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Wait, how do we find initial velocity?

Thanx for help.
 
We don't. But since the problem asked for the "velocity attained" (i.e. the increase in velocity), we can take it to be 0- that way the final velocity WILL be the increase in velocity.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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