Velocity-Time Graph: Dog's Position

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SUMMARY

The discussion focuses on calculating the velocity of a dog based on its position recorded in a graph. The velocities determined for three segments are A = 2 m/s, B = 0 m/s, and C = -2.42 m/s. Participants discuss the appropriate x-values for the Velocity-Time Graph, suggesting using 10, 20, and 28.25 for the x-axis and the corresponding velocities for the y-axis. The conversation also clarifies that the dog returns to y = 0, emphasizing the importance of accurately interpreting the graph's data points.

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  • Understanding of basic kinematics
  • Familiarity with graph interpretation
  • Knowledge of Velocity-Time Graphs
  • Ability to calculate average velocity
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  • Learn how to construct Velocity-Time Graphs from position data
  • Study the principles of kinematic equations
  • Explore the concept of instantaneous velocity
  • Investigate the relationship between position, velocity, and acceleration
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Students studying physics, educators teaching kinematics, and anyone interested in understanding motion through graphical analysis.

aatari
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Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?
 

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For c, it looks like he moves 15 meters in 6.667 seconds. Edit: -> It looks like it intersects exactly where those two gridlines meet.
 
TomHart said:
For c, it looks like he moves 15 meters in 6.667 seconds. Edit: -> It looks like it intersects exactly where those two gridlines meet.
So you are saying the dog doesn't go all the to 0? So if that's the case is the velocity then 2.27 m/s?
 
aatari said:
Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?

upload_2017-2-20_6-12-16.png

aatari said:
Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?

The y values are 20 m, 20 m and 0 m, but it is more accurate to read Δx and Δy from the blue triangle.
upload_2017-2-20_6-12-16.png
 
The dog definitely goes to back to y = 0. I am just saying that the point x=26.6666, y = 5 is a lot easier to read than the point at y=0.
 
Ok that is interesting. Thank you guys!
 
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How did you get this number?
C = -2.42 m/s
 

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