Verify that cos(2x)-cos(4x)/sin(2x)+sin(4x)=tanx

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Superstring
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Homework Statement

I'm supposed to verify this:
[tex]\frac{cos(2x)-cos(4x)}{sin(2x)+sin(4x)}=tanx[/tex]

The attempt at a solution

I reworked it every way I could think of, but it just won't work. I got desperate so I plugged it into some site and it said it was not a real identity, so I now I'm thinking maybe my teacher had a typo or something.
 
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rock.freak667 said:
look up the sum to product formulas for sine and cosine. They should help.

I already know them, but I still can't figure it out.
 
Superstring said:
I already know them, but I still can't figure it out.

Try applying them.
 
rock.freak667 said:
Try applying them.

If you don't want to help then don't comment please.
 
Superstring said:
If you don't want to help then don't comment please.

Am I correct to assume you did not apply them?
 
rock.freak667 said:
Am I correct to assume you did not apply them?

No, you are not. Before I posted here I used the sum/dif identities, pythagorean identities, and double angle formulas. Everything I did resulted in a dead end.
 
Superstring said:
No, you are not. Before I posted here I used the sum/dif identities, pythagorean identities, and double angle formulas. Everything I did resulted in a dead end.

Is it possible that you can post your work using the sum to product identities?
 
You can factor out sin2x from the denominator. Resolve it further as 2 sinx cosx, and write the right side as sinx/cosx. Eliminate cosx (assuming it is not zero). Divide both sides by sinx, and rewrite 2(sinx)^2 as 1-cos(2x). You can see that the denominator is equal to the numerator.

ehild
 
Superstring said:
No, you are not. Before I posted here I used the sum/dif identities, pythagorean identities, and double angle formulas. Everything I did resulted in a dead end.
You didn't use the right ones then. You need the sum-to-product identities. If you use them, the answer pops out in like two lines.

Look for identities for [tex]cos a - cos b[/tex] and [tex]sin a + sin b[/tex].

If, in fact, you used those already and didn't get anywhere, post what you did because that's where the difficulty lies.