Verifying Math Problem: Can You Help?

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SUMMARY

The discussion centers on verifying the convergence of the series \(\sum_{k=1}^{\infty} (-1)^{k}\frac{x^{2k}}{4^{k}(k!)^{2}}\) and its relationship to the Bessel function of the first kind. Participants concluded that the radius of convergence is infinite, but noted that the series does not converge for every possible value of "x". The original poster's work was validated, with a suggestion to simplify the analysis by substituting \(x^2=w\) and focusing on the limit of the ratios. The omission of the k=0 term was acknowledged, though it was clarified that this does not impact convergence.

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It doesn't converge for every possible "x",as your "radius of convergence =infinite" might mean.

\sum_{k=1}^{\infty} (-1)^{k}\frac{x^{2k}}{4^{k}(k!)^{2}} =-\frac{x^{2}}{4}\ _{2}F_{1} \left(1,2,2;-\frac{x^{2}}{4}\right)


Daniel.
 
To simplify
there was no need to take the x's ...take x^2=w and just take the limit of the ratio's..

As per my knowledge it seems to me R is infinite
 
Well,try x=60.How big is the number...?

Daniel.
 
Thanks for the replies guys.

I have left it as R = infinity; seems the rest of the class got the same thing. So I'll just leave it at that
 
dextercioby said:
It doesn't converge for every possible "x",as your "radius of convergence =infinite" might mean.

\sum_{k=1}^{\infty} (-1)^{k}\frac{x^{2k}}{4^{k}(k!)^{2}} =-\frac{x^{2}}{4}\ _{2}F_{1} \left(1,2,2;-\frac{x^{2}}{4}\right)

You've missed the k=0 term, though this doesn't affect convergence. The OP's work is fine.

For interests sake, this thing is a Bessel function of the first kind (it's a solution to the d.e. xy''+y'+xy=0).
 

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