B View double slit from other end

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The discussion centers on the ability of our eyes and cameras to detect the direction of photons in a double slit experiment. It questions whether using a moving camera instead of a screen would allow us to determine which slit a photon or electron passed through. However, it clarifies that neither our eyes nor photon detectors can provide information about the past trajectory of the particles; they only indicate where an interaction occurred. The conversation also seeks video evidence of these concepts but notes difficulty in finding such resources. Ultimately, the limitations of detection methods in revealing the history of photons are emphasized.
Samina
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Can anyone please guide me to some online resource, which shows a light source behind a double slit?
Our eyes not only detect the visible spectrum of light; they can also show the direction the photons are coming from.

If, instead of a detecting screen, we use a moving camera or an array of cameras, can't we tell exactly which slit a photon / electron passed through?When viewing a light source behind a double slit, do we see light shining from both slits?

Let's say there is a light source, covered by a double slit. Now if we move out eyes / a camera from left to right in place of screen, what exactly do we see?

If there is some video of it online, can someone guide me to it? I couldn't find any myself.

Regards.
 
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Samina said:
Our eyes not only detect the visible spectrum of light; they can also show the direction the photons are coming from.
Neither our eyes nor any other photon detector do that. They just record that an interaction with a photon happened at a particular point in space; this tells us nothing about the past history of the detected particle, including where it came from.
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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