Visualize plane given by this equation

[asmCode]

Dear users,

I'm wondering if it is possible to visualize function (plane) given by this equation:

Ax + By + Cz - D == 0

I tried to use Plot3D function, but it allows only 2 variables.

How to do that?

regards

 

[Mark44]

Ax + By + Cz - D = 0
<==> Cz = -Ax - By + D
<==> z = -(A/C)x - (B/C)y + D/C, assuming C isn't 0.
Now you have z as a function of the variables x and y.

 

[oswaler]

,

I would suggest using a 3D graphing software such as Mathematica or MATLAB to visualize the plane given by the equation. These software programs have the capability to graph 3D functions and equations, including planes. Additionally, you can also use a graphing calculator with 3D capabilities to visualize the plane.

To graph the plane, you will need to set the equation equal to z and plot it in a 3D coordinate system. This will give you a 2D representation of the plane in 3D space. You can also manipulate the values of A, B, C, and D to see how it affects the shape and orientation of the plane.

Another option would be to plot the points that satisfy the equation and connect them to form the plane. This can be done in a 3D graphing software or manually by calculating the coordinates of the points and plotting them on a 3D graph.

In summary, using a 3D graphing software or a graphing calculator with 3D capabilities would be the most efficient way to visualize the plane given by this equation.