Visualizing Arbitrary Coordinate System - Example Needed

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SUMMARY

The discussion focuses on visualizing the differences between the accelerations of components and the overall acceleration in a plane polar coordinate system. The position vector is defined as r\mathbf{e}_r(\theta) = r(\cos \theta, \sin \theta), with component accelerations represented as \ddot r and zero. The overall acceleration is expressed as \ddot{\mathbf{r}} = \ddot r\mathbf{e}_r + 2\dot r \dot \theta \mathbf{e}_\theta + r(-\dot \theta^2 \mathbf{e}_r + \ddot \theta \mathbf{e}_\theta). The key confusion lies in understanding why the component accelerations do not equal the overall acceleration components.

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BLevine1985
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Hi I'm wondering if someone can illustrate with an example what I bracketed in blue? I'm having a hard time visualizing how it is that the accelerations of the components are NOT necessarily equal to the components of the acceleration...Much appreciated!
relative acceleration of geodesic in 3+ dimensions.png
 
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In plane polars, the position vector is r\mathbf{e}_r(\theta) = r(\cos \theta, \sin \theta). The accelerations of the components are therefore \ddot r and zero. However, the acceleration is <br /> \ddot{\mathbf{r}} = \ddot r\mathbf{e}_r + 2\dot r \dot \theta \mathbf{e}_\theta + r(-\dot \theta^2 \mathbf{e}_r + \ddot \theta \mathbf{e}_\theta) = (\ddot r - r\dot \theta^2)\mathbf{e}_r + (2\dot r \dot \theta + r\ddot \theta)\mathbf{e}_\theta.
 
How did you get the acceleration of the components as r-double-dot and zero?

I understand how you got the general acceleration of r-double dot but not the first part. Sorry it's been like 10 years since I took classical mechanics...
 

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