Voltage around a loop, half inside a capacitor and half outside

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
RubinLicht
Messages
131
Reaction score
8

Homework Statement


This is not a homework problem, I'm working through griffiths Electrodynamics on my own.
upload_2019-2-20_13-25-2.png


Homework Equations


upload_2019-2-20_13-25-32.png

when there is an emf source, since electrosatic fields integrate to zero around a loop

The Attempt at a Solution


The solution claims that since the integral of f (force per charge) around the a loop for any electrostatic field is zero, the emf is zero since that is the only field present.

However, when I thought about this problem, I reasoned that initially the charges in the wire would rapidly reorient themselves to cancel out the external field. and since the field is 0 through out the wire, and there isn't a source of emf that generates potential differences in the metal, the current is naturally zero. This is very different reasoning, and i don't think the solutions are valid. Can anyone confirm/deny please?
 

Attachments

  • upload_2019-2-20_13-25-2.png
    upload_2019-2-20_13-25-2.png
    21.6 KB · Views: 699
  • upload_2019-2-20_13-25-32.png
    upload_2019-2-20_13-25-32.png
    742 bytes · Views: 582
Physics news on Phys.org
The problem asks about "the emf in the loop". It's unclear what that means.
The reasoning offered explains why there should be no net emf in one complete trip around the loop, hence no sustained current. Your reasoning is that once the initial redistribution of charge settles down there is no net emf in any segment of the loop.
I see no contradiction, and both appear valid.