Volume of a Gas from a thermal decomposition

  • Chemistry
  • Thread starter DottZakapa
  • Start date
  • #1
239
17
Homework Statement:
Thermal decomposition of calcium hydrogen carbonate yields calcium carbonate water and carbon dioxide. Calculate the volume of carbon dioxide measured at 0 °C and 1.00 atm that is obtained by heating 80.0 grams of calcium carbonate
Relevant Equations:
gas laws
Ca(HCO3)2 -> CaCO3 + H2O + CO2

First I evaluate the moles of calcium carbonate (don't mind the units, just to save time)

##\frac {80.0}{40,00+12.01+3*16,00}= 0,799 mol##

From the equation, correct me if I am wrong , one mole of CaCO3 is proportional to one mole of CO2, so from this I can say that also CO2 has 0,799 mol.

Using the ideal gas law equation PV=nRT, I can compute V:

##V=\frac{nRT}{P} ##

inserting the values, I don't get the expected result, so I suspect that something is wrong, Any help ?
 

Answers and Replies

  • #2
239
17
ok problem solved, there was a typo in the book.
it should be 80 g of calcium hydrogen carbonate, not calcium carbonate. with that correction the results match.
By the way, how is possible to delete a post?
 

Related Threads on Volume of a Gas from a thermal decomposition

  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
3
Views
5K
Replies
4
Views
3K
  • Last Post
Replies
5
Views
1K
Replies
1
Views
2K
  • Last Post
Replies
2
Views
10K
Replies
1
Views
6K
Replies
3
Views
4K
  • Last Post
Replies
2
Views
12K
  • Last Post
Replies
6
Views
2K
Top