Volume of a Gas from a thermal decomposition

[DottZakapa]

Homework Statement

Thermal decomposition of calcium hydrogen carbonate yields calcium carbonate water and carbon dioxide. Calculate the volume of carbon dioxide measured at 0 °C and 1.00 atm that is obtained by heating 80.0 grams of calcium carbonate

Relevant Equations

gas laws

Ca(HCO₃)2 -> CaCO₃ + H₂O + CO₂

First I evaluate the moles of calcium carbonate (don't mind the units, just to save time)

$\frac {80.0}{40,00+12.01+3*16,00}= 0,799 mol$

From the equation, correct me if I am wrong , one mole of CaCO₃ is proportional to one mole of CO₂, so from this I can say that also CO₂ has 0,799 mol.

Using the ideal gas law equation PV=nRT, I can compute V:

$V=\frac{nRT}{P}$

inserting the values, I don't get the expected result, so I suspect that something is wrong, Any help ?

 

[DottZakapa]

ok problem solved, there was a typo in the book.
it should be 80 g of calcium hydrogen carbonate, not calcium carbonate. with that correction the results match.
By the way, how is possible to delete a post?