MHB Volume of $E$ in $\mathbb{R}^4$ - AMM

  • Thread starter Thread starter MountEvariste
  • Start date Start date
  • Tags Tags
    Volume
Click For Summary
The problem involves determining the volume of the set $E$ in $\mathbb{R}^4$ defined by the inequality $(ax+by)^2+(cx+dy)^2 \le x^2+y^2$ for all real numbers $x$ and $y$. This inequality describes a geometric condition that relates to the preservation of lengths under a linear transformation represented by the coefficients $a, b, c, d$. The volume of $E$ can be interpreted as the set of transformations that do not increase the length of vectors in $\mathbb{R}^2$. The solution requires analyzing the constraints imposed by the inequality and potentially using techniques from linear algebra and geometry. Ultimately, the volume of the set $E$ is a significant result in understanding the behavior of linear transformations in higher dimensions.
MountEvariste
Messages
85
Reaction score
0
Let $E$ be the set of all real $4$-tuples $(a, b, c, d)$ such that if $x, y \in \mathbb{ R}$, then:
$(ax+by)^2+(cx+dy)^2 \le x^2+y^2$.
Find the volume of $E$ in $\mathbb{R}^4$.​

Source: AMM.
 
Mathematics news on Phys.org
Hint:

Show that $E$ is defined by the inequality $a^2 +b^2 +c^2 +d^2 \leqslant 1+(ad −bc)^2$ with $a^2 +c^2 \leqslant 1$ and $b^2 +d^2 \leqslant 1$.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 0 ·
Replies
0
Views
335