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Wacky trig. I am totally lost.

  1. Jan 24, 2009 #1
    Intersecting triangles.

    1. The problem statement, all variables and given/known data

    Find x

    [​IMG]

    2. Relevant equations
    trig and inverse trig functions?

    3. The attempt at a solution

    I have no idea how to solve this. When I try and use the trig that I know to find the lengths, I also end up having to depend on other variables.

    The only thing I was able to find out is that the angle opposite the 12 is twice the that of the 6.
     
    Last edited: Jan 24, 2009
  2. jcsd
  3. Jan 24, 2009 #2

    Dick

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    Science Advisor
    Homework Helper

    The TANGENT of the angle opposite 12 is twice the tangent of the angle opposite 6, if that's what you mean. But no trig necessary here. It's all similar triangles. Write down some relations you get from similarity.
     
    Last edited: Jan 24, 2009
  4. Jan 24, 2009 #3
    Oh. Thanks for the tip. I got it now.
     
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