Wall Cavity Insulation Question?

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jake96
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Homework Statement




Hi guys, I have read this question over and over and have no idea where to start, would anyone be able to help.

The Question

Up to 20% of all heat lost in domestic dwellings occurs through walls. Many modern Australian homes are built by constructing walls using ‘cavity concrete blocks’ which have at least a 75 mm air gap or ‘cavity’ as part of their design.

Consider a home built using cavity concrete blocks and compare this to using two other construction materials; brick and aluminium siding. By investigating the heat flow through an external wall,

a) outline the range of assumptions you make.

b) determine, using appropriate calculations to support your answer, the required equivalent
thickness of a home's wall, in order to give the same amount of insulation as a cavity concrete
block wall if the wall is made of
i) brick.
ii) aluminium siding.

c) Discuss comparisons between the individual construction materials.

Thanks


Homework Equations



no idea

The Attempt at a Solution



don't know where to start
 
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They are asking you to compare the thermal performance of three different wall constructions.

Cavity block
Solid Brick
Aluminum (I'm not familiar with this type).

How about you start by calculating the thermal resistance of a cavity concrete block wall ? They are made up of a sandwich of concrete block - air - concrete block. Should be possible to find the data you need (eg typical thickness of each layer and thermal resistance of each material).
 
ok, I've found the thermal conductivity of the four materials
air: 0.024
Aluminium: 205
Brick: 0.15
Concrete: 0.55

and found thickness for concrete block (in accordance to pictures from homework sheet)
concrete (30mm)-air (75mm)- concrete (30mm)

would this be the resistance of the cavity concrete block?
=.03/.55+.075/.024+.03/.55 (thickness/conductivity)
=3.234Km^2/W
 
also using a wall of 1mx1m so its not a hassle in calculations
 
jake96 said:
ok, I've found the thermal conductivity of the four materials
air: 0.024
Aluminium: 205
Brick: 0.15
Concrete: 0.55

and found thickness for concrete block (in accordance to pictures from homework sheet)
concrete (30mm)-air (75mm)- concrete (30mm)

would this be the resistance of the cavity concrete block?
=.03/.55+.075/.024+.03/.55 (thickness/conductivity)
=3.234Km^2/W
Good. Now, how thick would these other individual materials have to be to give this same resistance?

Chet
 
Brick
3.234=x/.15
=485mm

aluminium
3.234=x/205
=663m

this seems a little extreme for the aluminium
 
so these sort of calculations would be correct considering no other outside influence,

in reality this value would be much lower due to reflection and other attributes
 
What formula did you use to find the thermal conductivity?