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B Wave function, units in the argument

  1. Oct 29, 2016 #1
    I will be very grateful if someone could explain to me the following, in the most simple terms, f being a wave function :

    " ......f = f(x–ct). Let me explain the minus sign and the c in the argument.
    Time and space are interchangeable in the argument, provided we measure time in the ‘right’ units, and so that’s why we multiply the time in seconds with c, so the new unit of time becomes the time that light needs to travel a distance of one meter. That also explains the minus sign in front of ct: if we add one distance unit (i.e. one meter) to the argument, we have to subtract one time unit from it – the new time unit of course, so that’s the time that light needs to travel one meter – in order to get the same value for f."
     
  2. jcsd
  3. Oct 29, 2016 #2

    jtbell

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    Staff: Mentor

    Starting from the beginning, where is the first place that you get "stuck", and why?

    It will help people in giving you well-targeted answers, if you can be as specific as possible about what your difficulties are.
     
  4. Oct 29, 2016 #3
    I guess I am stuck with the arithmetic : if I multiply time in sec. with speed c which is meters over second , how arithmetically do I get a unit of time corresponding to a 1 meter distance ?
     
  5. Oct 29, 2016 #4
    I don't understand : ".. we multiply the time in seconds with c, so the new unit of time becomes the time that light needs to travel a distance of one meter." thank you if you can rephrase this for me !
     
  6. Oct 29, 2016 #5

    bhobba

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    Science Advisor
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    Time and space are not interchangeable, all SR is is some transformations between so called inertial frames.

    I think you first need to see a proper derivation of the transformations:
    http://www2.physics.umd.edu/~yakovenk/teaching/Lorentz.pdf

    We sometimes like to write our equations in forms applicable to all inertial frames. In that case sometimes people get loose and say distances are like c times time because in equation 29 above is invariant under such an interpretation.

    Its like you have a rod too big for a door so you rotate it to fit through. The length of the rod hasn't changed - just its x and y coordinates. Same with equation 29 if you are being a bit loose in your thinking - thinking of ct as a distance makes the equation seem more sensible. Its just like the Pythagoras theorem of geometry but you have a minus sign. This is given the fancy name of hyperbolic rotation.

    Thanks
    Bill
     
  7. Oct 29, 2016 #6
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