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## Homework Statement

In Fig. 17-35, sound with a 15.6 cm wavelength travels rightward from a source and through a tube that consists of a straight portion and a half-circle. Part of the sound wave travels through the half-circle and then rejoins the rest of the wave, which goes directly through the straight portion. This rejoining results in interference. What is the smallest radius r (cm) that results in an intensity minimum at the detector? (Take the speed of sound to be 343 m/s.)

## Homework Equations

If it wants the minimum intensity, we have to minimize the following equation: I = P/(4pi*r^(2)), where I is intensity, P equals power, and r equals radius. But then again, I also think of derivative when I hear maximum/minimum values...

## The Attempt at a Solution

343/15.6 = 21.99 Hz = frequency

2pi * frequency = angular velocity = 138.15

k = wave number = 0.403

So, these are the values we know, but I do not know how to manipulate them into the formula above...maybe I'm using the wrong formula?! Please help! I appreciate all the help. Thanks a bunch!