Weak Form of the Poisson Problem

  • Context: Graduate 
  • Thread starter Thread starter Morberticus
  • Start date Start date
  • Tags Tags
    Form Poisson Weak
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
Morberticus
Messages
82
Reaction score
0
Hi,

I know the weak form of the Poisson problem

[itex]\nabla^2 \phi = -f[/itex]

looks like

[itex]\int \nabla \phi \cdot \nabla v = \int f v[/itex]

for all suitable [itex]v[/itex]. Is there a similarly well-known form for the slightly more complicated poisson problem?

[itex]\nabla (\psi \nabla \phi ) = -f[/itex]

I am writing some finite element code and variational/weak forms are very handy.

Thanks in advance
 
Last edited:
Physics news on Phys.org
Morberticus said:
Hi,

I know the weak form of the Poisson problem

[itex]\nabla^2 \phi = -f[/itex]

looks like

[itex]\int \nabla \phi \cdot \nabla v = \int f v[/itex]

for all suitable [itex]v[/itex]. Is there a similarly well-known form for the slightly more complicated poisson problem?

[itex]\nabla (\psi \nabla \phi ) = -f[/itex]

I am writing some finite element code and variational/weak forms are very handy.

Thanks in advance

By the product rule
[tex] \int_V v\nabla \cdot(\psi \nabla \phi)\,dV = \int_V\nabla\cdot(v\psi \nabla \phi) - \psi (\nabla \phi) \cdot (\nabla v)\,dV = \int_{\partial V} v\psi \nabla \phi \cdot dS - \int_V\psi (\nabla \phi) \cdot (\nabla v)\,dV[/tex]
and hence the weak form of [itex]\nabla \cdot(\psi\nabla\phi) = - f[/itex] is
[tex] \int_V \psi (\nabla \phi) \cdot (\nabla v)\,dV = \int_V fv\,dV[/tex]
 
  • Like
Likes   Reactions: 1 person