Webassign even my ta's didn't know what to do ? and im in intro to physics

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SUMMARY

The discussion centers on solving a physics problem involving a 33-ohm resistor made from copper wire with a total mass of 12 grams. The key equations involved are Ohm's Law for resistivity, R = ρ(L/A), and the mass-volume relationship, m = density × volume. The challenge arises from having two unknowns—length (L) and diameter (d)—which complicates the solution. Participants highlight the need to manipulate these equations to isolate variables and find the required dimensions of the wire.

PREREQUISITES
  • Understanding of Ohm's Law and resistivity (R = ρ(L/A))
  • Knowledge of mass and volume relationships (m = density × volume)
  • Familiarity with the properties of copper, including its resistivity
  • Basic algebra skills for solving equations with multiple variables
NEXT STEPS
  • Review the properties of copper, specifically its resistivity at room temperature
  • Learn how to manipulate equations with multiple variables in physics
  • Study the concept of cross-sectional area and its relation to wire diameter
  • Explore practical applications of resistivity in electrical engineering
USEFUL FOR

This discussion is beneficial for physics students, particularly those in introductory courses, as well as educators and teaching assistants who assist with problem-solving in physics contexts.

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webassign even my ta's didn't know what to do... ?... and I am in intro to physics

Homework Statement


A 33 ohm resistor is made from a coil of Cu wire whose total mass is 12g. (a)What is the diameter of the wire and (b) how long is it ? ( give you answer in m)



Homework Equations


one equation my ta tried to use was (R) = (resistivity) x (L/A)


The Attempt at a Solution


no idea... we can't figure out where to go because the equation has both length and radius (in the equation for A of the cross section of the wire) as variables... this is the only question left on my webassign and i have 30 mins left... please help
 
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There is a mass in the problem. There's a second equation that says mass=density*volume=density*length*area.
 


Two equations, two unknowns. Solve:

[tex]R=\rho \frac{L}{A}[/tex] and [tex]m=dV=dAL[/tex] where d is density and rho is resistivity
 

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