What are the conditions for the divergence of a function of r to be true?

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    Divergence Function
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SUMMARY

The divergence of a function of r, represented as \(\nabla \cdot \mathbf{f}(\mathbf{r})\), requires specific conditions on the vector field \(\mathbf{f}(\mathbf{r})\). For instance, when \(\mathbf{f}(\mathbf{r}) = \hat{\mathbf{x}}\), the divergence is zero, leading to the conclusion that \(\frac{\partial}{\partial r}(r^2 |\mathbf{f}(\mathbf{r})|) = 2r\). This indicates that the relationship resembles a differential equation rather than a straightforward identity. Understanding these conditions is crucial for accurately applying divergence in vector calculus.

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Why is this true?

<br /> \vec \bigtriangledown \cdot \vec f ( \vec r ) = \frac {\partial}{\partial r} (r^2 | \vec f ( \vec r ) | )<br />
 
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It's not, at least not without some conditions on \mathbf{f}(\mathbf{r}) that you haven't given us. Take \mathbf{f}(\mathbf{r}) = \hat{\mathbf{x}}, for example. The divergence is zero, and the magnitude is just one, so

\frac{\partial}{\partial r}(r^2 |\mathbf{f}(\mathbf{r})|) = \frac{\partial}{\partial r}(r^2) = 2r

\nabla \cdot \mathbf{f}(\mathbf{r}) = \partial_r(r^2|\mathbf{f}(\mathbf{r})|) looks more like a differential equation to be solved rather than an identity.
 

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