What Are the Key Characteristics of Henon Attractors?

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Homework Help Overview

The discussion revolves around Henon Attractors, specifically focusing on the Henon map defined by recursive equations. The original poster is tasked with finding a fixed point within the chaotic behavior of the system, noting confusion regarding an additional term in the equation provided by their textbook.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to find the fixed point by equating the variables in the Henon map. They express confusion about an extra term in the equation they derived compared to the textbook. Some participants suggest re-evaluating the math to clarify the discrepancy.

Discussion Status

The discussion is ongoing, with participants exploring the mathematical derivation of the fixed point. There is a recognition of a misunderstanding regarding the subtraction of terms, and some guidance has been offered on formatting LaTeX equations.

Contextual Notes

The original poster is working under the constraints of a homework assignment, which may limit the information they can access or the methods they can use to solve the problem.

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1. Homework Statement

I am studying Henon Attractors. The Henon map is recursively defined as follows:

x_{t+1} = a - x^2_{t} + by_{t}<br /> y_{t+1} = x_{t}

I am supposed to find the fixed point (may be unstable) that is contained with the chaotic behavior

The Attempt at a Solution



It is clear that to find the fixed point would be when x_{t+1}, x_{t}, y_{t}
are all equal (Lets call them all x_{b}). It seemed obvious to just plug in
x_{b} and solve the quadratic, but the book had an extra term in the answer and I do not know where it came from:
-x^2_{b} + (b-1) x_{b} +a = 0. Where did the -1 in the b-1 term come from?
 
Last edited:
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If you just plug in x_b for x_t, y_t, and x_{t+1}, then the equation you get is exactly what the book says. Do your math again.
 
Oh, yes, the x_{b} on the left side is subtracted from the right to make it equal to 0. Duh!

Could you now how I insert a new line in the Latex equation? I can't seem to keep those two first equations from running together.
 
MathAmateur said:
Oh, yes, the x_{b} on the left side is subtracted from the right to make it equal to 0. Duh!

Could you now how I insert a new line in the Latex equation? I can't seem to keep those two first equations from running together.

The latex symbol for new line is \\
 
I did the following and got the following result:

x_{t+1} = a - x^2_{t} + by_{t} \\
y_{t+1} = x_{t}

x_{t+1} = a - x^2_{t} + by_{t}\\<br /> y_{t+1} = x_{t}
 

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