What are the possible solutions to (x^2-4)(x+3)=0?

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SUMMARY

The equation (x^2-4)(x+3)=0 can be solved by applying the zero product property, which states that if the product of two functions equals zero, at least one of the functions must equal zero. This leads to two separate equations: x^2-4=0 and x+3=0. Solving these gives the solutions x=2, x=-2, and x=-3. Thus, the complete solution set for the equation is {2, -2, -3}.

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(x^2-4)(x+3)=0
 
Mathematics news on Phys.org
As always, we can't do your homework for you. What are your thoughts on the problem?

Hint: If f(x)g(x) = 0 that implies f(x) = 0 or g(x) = 0.
 

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