What are the reagents in an iodoform reaction

  • Thread starter Thread starter lioric
  • Start date Start date
  • Tags Tags
    Reaction
Click For Summary

Discussion Overview

The discussion revolves around the reagents involved in the iodoform reaction, specifically in the context of a homework problem related to organic reactions. Participants explore the necessary reagents for the reaction involving butan-2-one and the subsequent formation of propanoic acid and iodoform.

Discussion Character

  • Homework-related
  • Exploratory
  • Technical explanation

Main Points Raised

  • One participant identifies sodium hydroxide and iodine as necessary for the iodoform reaction.
  • Another participant questions the organic products formed when combining sodium hydroxide and iodine in water, suggesting that 2-butanone is also involved.
  • There is a mention of sodium iodide (NaI) and sodium hypoiodite (NaOI) as products in the reaction.
  • Participants discuss the organic products resulting from the combination of 2-butanone, sodium hydroxide, and iodine, with one suggesting iodoform and sodium propanoate as the products.
  • One participant references two different sources regarding the formation of carboxylic acids from methyl ketones in haloform reactions, noting variations in the explanation.
  • Another participant suggests that to convert sodium propanoate to propanoic acid, a strong acid like HCl or H2SO4 is needed.
  • There is a reiteration that combining a salt with an acid results in a weaker acid and another salt.

Areas of Agreement / Disagreement

Participants express different views on the reagents and products involved in the iodoform reaction, with no consensus reached on the exact nature of reagent R or the organic products formed. The discussion remains unresolved regarding the specifics of the reaction and the necessary steps to achieve the desired products.

Contextual Notes

Some participants reference different sources that provide varying explanations for the reactions involved, indicating potential limitations in understanding or definitions used in the discussion.

lioric
Messages
335
Reaction score
26

Homework Statement


this question is about the organic reactions shown in the diagram. ( diagram shows that butan2one is reaction with a reagent P and Q and then reagent R and forms propanoic acid and iodoform)

a)name the reagents P and Q used in reaction 1.
b) identify the reagent R used in reaction 1 and explain why it is needed

Homework Equations


I do know that for iodoform reaction you need sodium hydroxide in iodine solution
But I'm wondering what the Reagent R is

The Attempt at a Solution

 
Physics news on Phys.org
lioric said:
I do know that for iodoform reaction you need sodium hydroxide in iodine solution
What are the products you get if you just put in sodium hydroxide and iodine in water?
Edit: and of course 2-butanone.
 
Last edited:
TeethWhitener said:
What are the products you get if you just put in sodium hydroxide and iodine in water?
Edit: and of course 2-butanone.

NaI and NaOI and water
 
lioric said:
NaI and NaOI and water
What are the organic products?
Edit: maybe my edit in post 2 wasn’t clear. When you combine 2-butanone, sodium hydroxide, and iodine in water, what are the organic products?
 
TeethWhitener said:
What are the organic products?
Edit: maybe my edit in post 2 wasn’t clear. When you combine 2-butanone, sodium hydroxide, and iodine in water, what are the organic products?

Iodoform and sodium propanoate
 
lioric said:
Iodoform and sodium propanoate
So if you want to end up with propanoic acid, what do you have to do?
 
TeethWhitener said:
So if you want to end up with propanoic acid, what do you have to do?

I have seen two versions of this

1) In a haloform reaction with iodine, bromine, or chlorine, methyl ketones are converted into the corresponding carboxylic acid and haloform. (from site chemgapedia
http://www.chemgapedia.de/vsengine/...ik/c_acid/synthese_von_carbonsaeuren.vlu.html

2) the other from McMurry organic chemistry textbook saying that in if we use excess halogen and base than it will form the carboxilic acid
And this link shows it too
https://goo.gl/images/miAQfp
 
Last edited:
You’re overthinking things. If you have sodium propanoate and you want propanoic acid, what do you need to do?
 
TeethWhitener said:
You’re overthinking things. If you have sodium propanoate and you want propanoic acid, what do you need to do?

Add a strong acid like HCl or H2SO4

Salt + acid makes a weaker acid and another salt
 
  • #10
lioric said:
Add a strong acid like HCl or H2SO4

Salt + acid makes a weaker acid and another salt
Right. So now just put it all together.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 28 ·
Replies
28
Views
6K
  • · Replies 1 ·
Replies
1
Views
7K
Replies
1
Views
4K
Replies
1
Views
3K
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 1 ·
Replies
1
Views
3K