What are the real and complex roots of z = exp(-z)?

  • Thread starter Thread starter gmans
  • Start date Start date
  • Tags Tags
    Complex Roots
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
3 replies · 7K views
gmans
Messages
1
Reaction score
0
of the equation
z= exp(-z)

could someone possibly point me in the right direction to start this problem?
this area of math is still new to me so please go easy
thanks
 
Physics news on Phys.org
I moved this thread to the homework section. gmans, what do you mean by the equation that you have written? What is "exp" representing?
 
Probably, he means:
[tex]z=e^{-z}[/tex]
 
That's a fun problem. I say start by defining z=a+ib where a and b are real numbers and also note z=|z|exp(i[itex]\Phi[/itex]) the polar form of z, so that you're looking for the solutions to

[tex]|z|e^{i\Phi}=e^{-a-ib}[/tex]

And use the fact that two complex numbers are equal iff their modulus are the same and their polar angle are the same up to a difference of [itex]2n\pi[/itex], [itex]n\in\mathbb{Z}[/itex].
 
Last edited: