What are the solutions to these diaphontine equations?

[Sam_]

So help me with this:

this are simultanious equations.

1/(x^2) + x^2 -7 = 0
&&
1/x + x -y = 0

What is y?

 

[CompuChip]

The first one doesn't depend on y, so tackle that one first.
Multiply the first by x^2 and solve it, then plug the result into the second and solve for y.

 

[HallsofIvy]

In what sense is this "diophantine equations"? A Diophantine equation is a single equation to be solved in terms of (positive) integers.

 

[dodo]

In fact, if these are expected to be solved in integers, there is only one (and plain sight obvious) solution for the second equation.

P.S.: A solution which does not check on the first equation, anyway.
P.P.S.: Oh, sorry, two obvious solutions. I was forgetting there is such thing as negative numbers. Doh! Neither will fit the first equation.

 

[CompuChip]

In fact, if these are expected to be solved in integers, there is only one (and plain sight obvious) solution for the second equation.

It is plain sight obvious how to solve this system and get the two solutions to it, after which it will be even more plain sight obvious whether they are integers (if not, clearly there are no integer solutions).