What Are Three Uses of Rhodium as a Catalyst?

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SUMMARY

Rhodium serves as a catalyst in three significant chemical reactions: the reduction of nitrogen oxides, the carbonylation of methanol, and the vapor conversion of carbon monoxide to carbon dioxide. The balanced equations for these reactions are as follows: for nitrogen oxides, 2NO_x → xO_2 + N_2; for carbonylation, H3COH + CO → H3CCOOH. However, the vapor conversion reaction CO + H2O → CO2 + H+ is technically impossible to balance, indicating that the proposed reaction must be revised for accuracy.

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Homework Statement


I was reviewing chem the other day, and noticed this question can anyone clarify my answer for me and let me know if I'm correct.

The question states:

Describe three uses of rhodium as a catalyst. ( include both a written description and the balancecd equation).

Homework Equations

The Attempt at a Solution


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The rhodium in this case will help catalyze the reduction of nitrogen oxides [2NO_x → xO_2+N_2]. Secondly another use would be of the carbonylation reaction by adding a carbon dioxide molecule into methanol. H_3 COH+CO→H_3 CCOOH. Thirdly and finally, it can be used as vapour conversion of carbon oxide to carbon dioxide, which reduces water by adding a carbon dioxide molecule which looks like this: CO+H_2 O→CO_2+H^+
 
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The last reaction - as written - is technically impossible (can't be balanced).
 
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Borek said:
The last reaction - as written - is technically impossible (can't be balanced).
Hi Borek, it's been a while! First off thanks for the reply it is very much appreciated.
But there is vapour conversion of carbon oxide to carbon dioxide right?
Also why exactly is it impossible?
 
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You can't balance the equation, so the process can't follow it.

Doesn't mean there is no vapor conversion of oxides, just the reaction equation must be different.
 
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Borek said:
You can't balance the equation, so the process can't follow it.

Doesn't mean there is no vapor conversion of oxides, just the reaction equation must be different.
CO2 + OH ---> CO + H2O
Would it look more like this then?
 
No such thing as OH (unless you mean a hydroxyl radical, but radicals are so reactive they don't need a catalyst).

Plus, it still can't be balanced.
 
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Borek said:
No such thing as OH (unless you mean a hydroxyl radical, but radicals are so reactive they don't need a catalyst).

Plus, it still can't be balanced.
What exactly am I not understanding here?
Also is there any thing I should relearn to understand this better?
 
Catalyst can work only on real reactions - that means a balanced equation. Try to balance the two equations you posted.
 

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