What density does something have to have to be considered a black hole?

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SUMMARY

A black hole can theoretically form from any mass if it is compressed to a sufficient density. This critical density is defined by the condition where the Schwarzschild radius (r_s) is less than the actual radius (r) of the object. The mathematical relationship for this density is given by the formula ρ = (3/8)(c²/Gπr²), where G is the gravitational constant and c is the speed of light. This discussion emphasizes the importance of understanding the interplay between mass, density, and the Schwarzschild radius in the formation of black holes.

PREREQUISITES
  • Understanding of Schwarzschild radius and its significance in black hole physics.
  • Familiarity with basic concepts of mass, density, and volume in physics.
  • Knowledge of gravitational constant (G) and speed of light (c).
  • Ability to manipulate mathematical equations involving physical constants.
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  • Research the implications of the Schwarzschild radius in astrophysics.
  • Explore the concept of event horizons and their relation to black holes.
  • Study the role of density in the lifecycle of stars and black hole formation.
  • Learn about the mathematical derivations of black hole properties and their physical interpretations.
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Astronomers, physicists, and students studying astrophysics, particularly those interested in black hole formation and the underlying mathematical principles.

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"Any amount of mass at all can in principle be made to form a black hole if you compress it to a high enough density."

What is the high enough density?
 
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This high enough density is the density at which the schwarzchild radius of the object is less than the actual radius of the object.

Mathematically,
[tex]r_s=\frac{2Gm}{c^2}=r[/tex]
If you assume the object to be a uniform sphere, we can write its mass as the product of density and volume:
[tex]m=\rho V=\frac{4/3}\rho\pi r^3[/tex]

And substituting into the first equation,
[tex]r=\frac{2G(\frac{4/3}\rho\pi r^3){c^2}[/tex]
[tex]\rho=\frac{3}{8}\frac{c^2}{G\pi r^2}[/tex]

In a completely classical universe.
 

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