What Determines the Domain of f(g(x)) for Given Functions?

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SUMMARY

The domain of the composite function f(g(x)), where f(x) = sqrt(x-1) and g(x) = x^2, is determined to be x ≤ -1 or x ≥ 1. The function g(x) has a domain of all real numbers, but the output of g(x) must satisfy the condition of f(x) for the composite function to be valid. Therefore, the domain of f(g(x)) is expressed as {x | x ≤ -1 ∪ x ≥ 1}.

PREREQUISITES
  • Understanding of composite functions
  • Knowledge of square root functions
  • Familiarity with domain and range concepts
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of composite functions in detail
  • Learn about the domain and range of square root functions
  • Explore the implications of function transformations on domains
  • Investigate other types of functions and their compositions
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Students studying calculus, mathematics educators, and anyone interested in understanding function composition and domain determination.

Coco12
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Let's say f(x) = sqrt(x-1)
And g(x) =x^2

What is the domain of f(g(x))

Well the domain of g(x) is all real numbers and the equation for the new function is sqrt(x^2-1)

Am I right to say that the domain for f(g(x)) is x greater than or equal to 1 and less than and equal to -1??
 
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Coco12 said:
Let's say f(x) = sqrt(x-1)
And g(x) =x^2

What is the domain of f(g(x))

Well the domain of g(x) is all real numbers and the equation for the new function is sqrt(x^2-1)

Am I right to say that the domain for f(g(x)) is x greater than or equal to 1 and less than and equal to -1??
Yes. In a bit nicer form it is ##\{x | x \leq -1 \cup x \geq 1\}##.
 

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