What does e^(xln(y)) equal when x = -1.18?

[eddysd]

What does e^(xln(y)) equal?

EDIT: x being a number, -1.18

 

[gomunkul51]

e^(xln(y)) = (e^ln(y))^x = y^x

*@hgfalling corrected :)

 

[hgfalling]

Wait, what?

$$e^{x \ln y} = (e^{\ln y})^x = y^x$$

 

[eddysd]

ok, thankyou but it actually didn't help, my problem is below:

maCln(t/600)+mbCvln(t/500)=0

Where ma, C, mb and Cv are known, how do I work out t?

 

[Char. Limit]

Make both sides a power of e. But first, turn it into one logarithm.

$$a log(x) + b log(y) = log(x^a y^b)$$

 

[eddysd]

Doing that gives me:

(t/600)^(26x10^3)x(t/500)^(21.99x10^3)=0

Which doesn't seem solvable to me!

Any ideas?

 

[Dick]

Doing that gives me:

(t/600)^(26x10^3)x(t/500)^(21.99x10^3)=0

Which doesn't seem solvable to me!

Any ideas?

Try another log rule. Like ln(t/600)=ln(t)-ln(600).

 

[eddysd]

Thanks for all the help, think I've got it sorted now!