What does the symbol Vdash mean?
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
8 replies · 4K views
Physics news on Phys.org
voko
- 6,053
- 391
It is negation of [tex]\Vdash[/tex] and the latter means "entails".
weetabixharry
- 111
- 0
Yes, I saw the [itex]\Vdash[/itex] symbol listed as "entails" in Wikipedia's list of mathematical symbols. However, in that article, the explanation is "A [itex]\Vdash[/itex] B means the sentence A entails the sentence B, that is in every model in which A is true, B is also true."voko said:It is negation of [tex]\Vdash[/tex] and the latter means "entails".
I can't see how that applies to my example (which is not in the form[itex]A \nVdash B[/itex]).
- 1,089
- 10
How about : the cases described are excluded, i.e., the definition excludes the
cases n=k=0 ?
cases n=k=0 ?
weetabixharry
- 111
- 0
This still does not seem to make sense in the given context. The relevant phrase in full is:[tex]\mathrm{where \ } R_{n,0,k}(x) \ := \ \nVdash(n=k=0), \ \ R_{n,j,0} \ := \ \nVdash(n=j) \mathrm{ \ \ and \ \ } R_{n,j,k} \ := \ 0 \ \mathrm{else}[/tex]Bacle2 said:How about : the cases described are excluded, i.e., the definition excludes the
cases n=k=0 ?
weetabixharry
- 111
- 0
I've spent a long time trying to reverse engineer the phrase. My best guess is that the whole phrase (see previous post) could translate into the following two statements:
[tex]R_{n,0,k}=\left\{ <br /> \begin{array}{c}<br /> 1, \\ <br /> 0,<br /> \end{array}<br /> \begin{array}{l}<br /> \text{if }n=k=0 \\ <br /> \text{otherwise}<br /> \end{array}<br /> \right.[/tex]
[tex]R_{n,j,0}=\left\{ <br /> \begin{array}{c}<br /> 1, \\ <br /> 0,<br /> \end{array}<br /> \begin{array}{l}<br /> \text{if }n=j \\ <br /> \text{otherwise}<br /> \end{array}<br /> \right.[/tex]
Even if this is correct, there are other bits of notation that I don't understand... but I suppose I should start a new thread, as this one seems pretty dead.
[tex]R_{n,0,k}=\left\{ <br /> \begin{array}{c}<br /> 1, \\ <br /> 0,<br /> \end{array}<br /> \begin{array}{l}<br /> \text{if }n=k=0 \\ <br /> \text{otherwise}<br /> \end{array}<br /> \right.[/tex]
[tex]R_{n,j,0}=\left\{ <br /> \begin{array}{c}<br /> 1, \\ <br /> 0,<br /> \end{array}<br /> \begin{array}{l}<br /> \text{if }n=j \\ <br /> \text{otherwise}<br /> \end{array}<br /> \right.[/tex]
Even if this is correct, there are other bits of notation that I don't understand... but I suppose I should start a new thread, as this one seems pretty dead.
voko
- 6,053
- 391
Why don't you get in touch with the author of the article?
- 22,170
- 3,335
voko said:Why don't you get in touch with the author of the article?
Good idea. It looks like a typo. So you should ask the author.
weetabixharry
- 111
- 0
Yeah, I've E-mailed the author... fingers crossed that I get a reply, I suppose.voko said:Why don't you get in touch with the author of the article?
Similar threads
- cianfa72
- · Replies 5 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 5
- gmax137
- · Replies 2 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 2
- nomadreid
- · Replies 2 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 2
- Stephen Tashi
- · Replies 6 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 6
Undergrad
Symbol meaning in CP-violating angle
- Ranku
- · Replies 1 ·
- Quantum Physics
- Replies
- 1
- Kakashi
- · Replies 6 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 6
Graduate
Proving: Proof by Contradiction
- Klungo
- · Replies 5 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 5
- topsquark
- · Replies 4 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 4
- Terrell
- · Replies 4 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 4
- Sterling1
- · Replies 3 ·
- Set Theory, Logic, Probability, Statistics
- Replies
- 3