weetabixharry
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I would like to know what this symbol means:[tex]\nVdash[/tex]Specifically, in the main result of [link] (Theorem 1, at the top of p.4), it has:[tex]\nVdash(n=k=0)[/tex]
The discussion revolves around the meaning of the symbol Vdash, particularly in the context of a theorem referenced in a linked article. Participants explore its implications in mathematical logic and notation, focusing on its application and interpretation in specific cases.
Participants express uncertainty regarding the application of the Vdash symbol and its implications in the context provided. There is no consensus on its interpretation, and multiple viewpoints are presented without resolution.
Participants note confusion regarding the notation and its application, indicating that additional context or definitions may be necessary for full understanding.
Yes, I saw the [itex]\Vdash[/itex] symbol listed as "entails" in Wikipedia's list of mathematical symbols. However, in that article, the explanation is "A [itex]\Vdash[/itex] B means the sentence A entails the sentence B, that is in every model in which A is true, B is also true."voko said:It is negation of [tex]\Vdash[/tex] and the latter means "entails".
This still does not seem to make sense in the given context. The relevant phrase in full is:[tex]\mathrm{where \ } R_{n,0,k}(x) \ := \ \nVdash(n=k=0), \ \ R_{n,j,0} \ := \ \nVdash(n=j) \mathrm{ \ \ and \ \ } R_{n,j,k} \ := \ 0 \ \mathrm{else}[/tex]Bacle2 said:How about : the cases described are excluded, i.e., the definition excludes the
cases n=k=0 ?
voko said:Why don't you get in touch with the author of the article?
Yeah, I've E-mailed the author... fingers crossed that I get a reply, I suppose.voko said:Why don't you get in touch with the author of the article?