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What does this symbol mean (partial derivatives)

  1. Dec 27, 2008 #1
    Question : g(x,y) = x^3 - 3x^2 + 5xy - 7y^2

    Verify that ∇g(0,0) = 0

    I looked on wiki and it said the vector of partial derivatives, so my g(x,y) would become

    ∇g = (3x^2 - 6x + 5y, 5x -14y)

    so what do i do from here? i dont see what its asking, do i plug x and y as 0 and show I get 0? Where do i plug them into?
     
  2. jcsd
  3. Dec 27, 2008 #2

    Defennder

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    You plug them into the expression for ∇g. That's what ∇g(0,0) mean. What would you get then? Note that your final answer is a vector.
     
  4. Dec 27, 2008 #3
    so just a zero vector?
     
  5. Dec 27, 2008 #4

    Defennder

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    Yes, that's what you should get as the question said.
     
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