What else could we do? (p-adic expansion)

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The discussion focuses on finding the p-adic expansion of $\frac{1}{p}$ and $\frac{1}{p^r}$ within the field $\mathbb{Q}_p$. It is established that solving the congruences $px \equiv 1 \pmod{p^n}$ and $p^r x \equiv 1 \pmod{p^n}$ does not yield solutions, confirming that these values are not p-adic integers. The p-adic expansions are characterized by having all digits zero except for $a_{-1} = 1$ for $\frac{1}{p}$ and $a_{-r} = 1$ for $\frac{1}{p^r}$, with examples provided for 5-adic expansions.

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evinda
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Hello! (Wave)

I want to find the p-adic expansion of $\frac{1}{p}$ and $\frac{1}{p^r}$ in the field $\mathbb{Q}_p$.

So, do I have to solve the congruences $px \equiv 1 \pmod {p^n}, p^r x \equiv 1 \pmod { p^n }, \forall n \in \mathbb{N} $, respectively?

But.. these congruences do not have solutions, right? (Thinking)

What else could we do, in order to find the p-adic expansion of $\frac{1}{p}$ and $\frac{1}{p^r}$ in $\mathbb{Q}_p$ ? (Worried)
 
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If you are trying to express 1/p and 1/p^r as a list of p-adic integer digits,
{a0, a1, a2, ... }
then it is correct " these congruences do not have solutions"

These are not p-adic integers. The digit list has non-zero an, for n<0.

Case 1/p:
all digits zero except a-1 = 1

Case 1/p^r:
all digits zero except a-r = 1

Examples: 1/5 and 1/5^3 as 5-adic
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