What exactly is this question acting?

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Homework Help Overview

The discussion revolves around understanding the domain of the arcsin function and its application in a specific context. Participants are examining a question from a past exam that involves the relationship between the arcsin and sin functions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the phrasing of the original problem and its implications regarding the domain of arcsin. There is an exploration of whether arcsin(sin(-1)) equals -1, with some participants attempting to clarify the definitions involved.

Discussion Status

Some participants have provided insights into the properties of the arcsin function and its domain, suggesting that the value of arcsin(sin(-1)) is indeed defined. However, there is no explicit consensus on the interpretation of the original question's wording.

Contextual Notes

There is a noted confusion regarding the terminology used in the question, particularly the use of "acting" instead of "asking," which may affect the understanding of the problem. Additionally, the discussion highlights the importance of recognizing the specific domain of the arcsin function.

xdrgnh
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http://www.math.poly.edu/courses/ma0914/past_exams/MA922_Midterm_2001-05-23.pdf

The first questions that are asking about domain. If I recall right domain is the set which has all possible inputs for a function. I don't understand it means in this context.

Lol it wrote acting instead of asking.
 
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Hmm yeah that does look odd. I suppose what it's supposed to be trying to say is within the domain of arcsin(x), is the value of arcsin(sin(-1)) = -1?
 
Well then the answer would be yes because sin-1 is a number less then 1 and -1.
 
xdrgnh said:
Well then the answer would be yes because sin-1 is a number less then 1 and -1.

Nearly, the arcsin function is taken to be the inverse of the sin function on the domain [tex]x\in \left[-\frac{\pi}{2},\frac{\pi}{2}\right][/tex] and so because -1 is in this domain, then sin(-1) is defined and thus arcsin of that value is also defined, giving us back the value -1.
 

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