What Gases Were Detected in the Air Sample Test?

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SUMMARY

The air sample test indicated the presence of sulfur dioxide (SO2), carbon dioxide (CO2), and water (H2O). The blue color change of anhydrous CuSO4 confirmed the presence of water vapor, while the decolorization of acidified potassium permanganate (KMnO4) suggested the presence of a reducing agent, specifically SO2. The formation of a white precipitate in limewater confirmed the presence of CO2, as it reacts with calcium hydroxide to form calcium carbonate (CaCO3).

PREREQUISITES
  • Understanding of gas detection methods, specifically anhydrous CuSO4 and acidified KMnO4.
  • Knowledge of chemical reactions involving carbon dioxide and calcium hydroxide.
  • Familiarity with the properties of sulfur dioxide as a reducing agent.
  • Basic chemistry concepts related to gas solubility and precipitation reactions.
NEXT STEPS
  • Research the chemical properties and reactions of sulfur dioxide (SO2).
  • Study the use of potassium permanganate (KMnO4) as an oxidizing agent in redox reactions.
  • Explore the methods for detecting water vapor in gas samples using anhydrous CuSO4.
  • Investigate the chemical process of limewater testing for carbon dioxide (CO2).
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Chemistry students, environmental scientists, and laboratory technicians involved in gas analysis and detection methods.

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Question :
Air sample sujected to following tests. The anhydrous CuSO4 turned blue, the acidified KMnO4 was decolourised and white ppt was seen in limewater.

Which of the following sets of gasas was present in the air sample?

a) SO2, CO2 and H2O
b) SO2, CO and H2O
c) CO, H2 and H2O
d) CO2, H2O and CO

someone please tell me and explain why.

thank you.
 
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Please read the sticky thread at the top of this subforum. We can not help you unless you first show your own effort.
 
does saying it's either a or d because CO2 is produced when the limewater turns chalky constitute as showing my own effort?
 
It's not asking what is produced, it is asking what is absorbed / reacted.
But you are correct by accident, CO2 + Ca(OH)2 gives you a precipatate of CaCO3

'anhydrous' CuSO4 gives you a clue about the water but since water is in all the answers that doesn't really help.
You just have to think what does a strong oxidiser like KmnO4 do?
 

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