I think I had seen it elsewhere, but I can't found it now. What happen when photon passing through highly charged field?
Well, that is indeed what i asumed you meant to say in the first place. The answer i gave concerning photons stays the same.I think you misunderstand 'passing through highly charged field', my question like electron being accelerate by negative field, deflected by positive field...
Dunno 'bout that but fact is that uncharged particles (electrically as well as magnetically "un"charged) are NOT affected by the presence of the EM field. As a matter of fact, the electroncharge e expresses the strength of interaction of the EM force mediated by photons. In short : e is the coupling constant of the EM interaction. So, no e equals no EM interaction. It is as simple as that. Same counts for the magnetic part which is dual to the electric part.I remember there still be some kind of reaction under critic condition, I had read.
I just surf through internet find no article about 'photon hadronization', indeed I do, but all in mathematical expression, which I can't understand.Keep in mind that photons do NOT interact with photons (at least not directly, in higher order perturbation theory they do interact through hadronization but i am sure that will take us too far)
A photon does not pass through a very high EM field. Photons are the EM field, meaning that they are the quanta of vibrating EM fields. What i CAN tell you is that photons do not interact with photons in lowest order perturbation theory.OK, what I want is a direct and simple answer: What is the result when photon passing through very high EM field?
No not "some different travelling", i mean NO TRAVELLING AT ALL.The photon don't pass through high EM field? I don't understand. You mean photon undergoes some different traveling method within high EM field?
Why? You mean I cannot even started to shoot a real photon into the field?No not "some different travelling", i mean NO TRAVELLING AT ALL.
Actually, you ask an invalid question. Why ? Because it violates one of the foundations of QM. The particle wave duality states that you can EITHER use the particle picture (photons) OR the wavelike picture (EM waves which correspond to vibrating EM fields) but NOT BOTH AT THE SAME TIME. You are doing the latter because you use both photons and EM fields at the same time. So, either we talk about photons (WHICH DO NOT MUTUALLY INTERACT, except indirectly through hadronization) or we talk about EM fields.
edit : hadronization
what is the matter? at this high value will make something different?How HIGH of a field? Would 80 MV/m do?
That's too weak for anything noticable I suppose.How HIGH of a field? Would 80 MV/m do?
I don't know, I am asking you since you just said "high". This is vague and ambiguous. Remember, YOU were the one who asked this, and presumably, there was some REASON for you to be asking such a question, then I'm asking you what do you mean by "high". It would be silly for ME to be the one defining what YOU mean by "high field", wouldn't it?what is the matter? at this high value will make something different?