What happens when you commute Sx and Sz in spin operators?

[Dennmac]

So we know [Sz, Sx] = ihbar Sy (S with hats on) so what happens if you get [Sx, Sz]? Is it the same result? Just trying to work out if I've gone wrong somewhere

 

[PeroK]

So we know [Sz, Sx] = ihbar Sy (S with hats on) so what happens if you get [Sx, Sz]? Is it the same result? Just trying to work out if I've gone wrong somewhere

In general $[A, B] = - [B, A]$. The proof is as easy as they come.

 

[Dennmac]

Facepalm...thank you! Letters are swimming in front my eyes, I think it's time for a break!