MHB What is [2x] Notation? Continuity Question

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The question asks me to determine whether the function is continuous?
f(x)=1, x =0,1
f(x)=x+[2x], 0<x<1
what is this [2x]? I cannot find it in the textbook and during lecture we had no information given about this.View attachment 6413
 

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FallArk said:
The question asks me to determine whether the function is continuous?
f(x)=1, x =0,1
f(x)=x+[2x], 0<x<1
what is this [2x]? I cannot find it in the textbook and during lecture we had no information given about this.

Hi FallArk!

The $[x]$ notation indicates the floor function.
That is, rounding down to the nearest integer below $x$.
Btw, I prefer the notation $\lfloor x \rfloor$, which is more intuitive.
 
I like Serena said:
Hi FallArk!

The $[x]$ notation indicates the floor function.
That is, rounding down to the nearest integer below $x$.
Btw, I prefer the notation $\lfloor x \rfloor$, which is more intuitive.

Then if i get 1.2, the result would be 1?
 
FallArk said:
Then if i get 1.2, the result would be 1?

Yes.
$$[1] = [1.2] = [1.99] = 1$$
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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