What is an example of a non-closed subspace in a normed space?

Click For Summary
SUMMARY

The discussion centers on identifying non-closed subspaces within normed spaces, specifically within the context of continuous functions defined on the interval [0,1] with the supremum norm. It is established that the subspace of differentiable functions is not closed, as sequences of differentiable functions can converge to non-differentiable functions. Additionally, the linear span of a complete orthonormal set in Hilbert space is dense but not closed, exemplifying the concept further. The space of integrable functions on [0,1] with the L1 norm is also mentioned, highlighting that a Cauchy sequence of continuous functions can converge to a discontinuous function, which is outside the subspace.

PREREQUISITES
  • Understanding of normed vector spaces and Banach spaces
  • Familiarity with the supremum norm and L1 norm
  • Knowledge of differentiable functions and their properties
  • Concept of dense subsets in Hilbert spaces
NEXT STEPS
  • Study the properties of Banach spaces and their subspaces
  • Learn about the supremum norm and its implications for continuity
  • Explore the concept of dense subsets in Hilbert spaces
  • Investigate examples of Cauchy sequences in normed spaces
USEFUL FOR

Mathematicians, students of functional analysis, and anyone studying properties of normed spaces and their subspaces will benefit from this discussion.

quasar987
Science Advisor
Homework Helper
Gold Member
Messages
4,796
Reaction score
32
What would be an example of a not (topologically) closed subspace of a normed space?
 
Mathematics news on Phys.org
Consider the space of continuous functions f:[0,1]->R with the supremum norm
\Vert f\Vert=\sup |f(x)|. This is a normed vector space (in fact, a Banach space). The subspace of differentiable functions is not closed.

mathboy said:
R is a normed space, so take any open interval.

That's not a linear subspace though.
 
the linear span of a complete orthonormal set in hilbert space. it is dense, since all vectors are infinite series expansions of the, but not closed since not all vecors are finite linear combinations.

i.e. a hilbert basis is an o.n. set whose span is dense.
 
Or the set of indefinitely differentiable functions with compact support defined on R as a subset of L^p(R). It is a proper subspace and it is dense, therefor it is not closed.

I get the idea, thanks!
 
why the space of diffrental function not closed help me pleas quakly
 
lady99 said:
why the space of diffrental function not closed help me pleas quakly

Because you can find an example of a sequence of differentiable functions that converge uniformly to a non-differentiable function.
 
Simply take the space X of integrable functions on [0,1], equipped with the L_1 norm, and consider the subspace Y of continuous functions on [0,1]: one can find a Cauchy sequence of functions in Y whose limit is integrable but discontinuous, and is hence no longer in Y.
 
pleas give me eaxample
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K