What is an example of a non-closed subspace in a normed space?
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gel
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Consider the space of continuous functions f:[0,1]->R with the supremum norm
[itex]\Vert f\Vert=\sup |f(x)|[/itex]. This is a normed vector space (in fact, a Banach space). The subspace of differentiable functions is not closed.
That's not a linear subspace though.
[itex]\Vert f\Vert=\sup |f(x)|[/itex]. This is a normed vector space (in fact, a Banach space). The subspace of differentiable functions is not closed.
mathboy said:R is a normed space, so take any open interval.
That's not a linear subspace though.
Science Advisor
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the linear span of a complete orthonormal set in hilbert space. it is dense, since all vectors are infinite series expansions of the, but not closed since not all vecors are finite linear combinations.
i.e. a hilbert basis is an o.n. set whose span is dense.
i.e. a hilbert basis is an o.n. set whose span is dense.
lady99
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why the space of diffrental function not closed help me pleas quakly
g_edgar
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lady99 said:why the space of diffrental function not closed help me pleas quakly
Because you can find an example of a sequence of differentiable functions that converge uniformly to a non-differentiable function.
KunalNC
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Simply take the space X of integrable functions on [0,1], equipped with the L_1 norm, and consider the subspace Y of continuous functions on [0,1]: one can find a Cauchy sequence of functions in Y whose limit is integrable but discontinuous, and is hence no longer in Y.
lady99
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pleas give me eaxample
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