- #1
smize
- 78
- 1
#include <iostream>
#include <string>
using namespace std;
void str2hex(string str) {
int strlen = str.length(); // Assign the length of input/str to strlen
string hex[strlen]; // Initialize the Array hex with the length of the string for (int x = 0; x < strlen; x++){ // Create a for loop assigning the values of the string to hex as hexadecimal values. if (str[x] == " "){
hex[x] = 20;
}
}
}
int main()
{
string input; // Declaring the string which will be converted into HEX
getline(cin,input); // Gets the user's input for the string
str2hex(input); // Inserts the user's input into the str2hex function
return 0;
}
In this program the issue is occurring on the line with if(str[x] == " ") {
the error I'm getting is: comparison with string literal results in unspecified behaviour
I can't figure out what is wrong. I am new to C++ so please don't scold me. Thank - you.
#include <string>
using namespace std;
void str2hex(string str) {
int strlen = str.length(); // Assign the length of input/str to strlen
string hex[strlen]; // Initialize the Array hex with the length of the string for (int x = 0; x < strlen; x++){ // Create a for loop assigning the values of the string to hex as hexadecimal values. if (str[x] == " "){
hex[x] = 20;
}
}
}
int main()
{
string input; // Declaring the string which will be converted into HEX
getline(cin,input); // Gets the user's input for the string
str2hex(input); // Inserts the user's input into the str2hex function
return 0;
}
In this program the issue is occurring on the line with if(str[x] == " ") {
the error I'm getting is: comparison with string literal results in unspecified behaviour
I can't figure out what is wrong. I am new to C++ so please don't scold me. Thank - you.