What is Conditional Probability and its Properties?

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SUMMARY

The discussion focuses on the definition and properties of conditional probability, specifically P(E|F), which is calculated as P(E|F) = (E∩F)/P(F) where P(F) ≠ 0. Key properties include P(S|F) = 1, the additive property for disjoint events P((A∪B)|F) = P(A|F) + P(B|F), and the complement rule P(E'|F) = 1 - P(E|F). The discussion also emphasizes the importance of visual aids like Venn diagrams for understanding these concepts.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with sample spaces and events
  • Knowledge of Venn diagrams for visual representation
  • Basic algebra for manipulating probability equations
NEXT STEPS
  • Study the Law of Total Probability
  • Learn about Bayes' Theorem and its applications
  • Explore advanced topics in probability theory, such as Markov Chains
  • Practice problems involving conditional probability using statistical software
USEFUL FOR

This discussion is beneficial for students of statistics, data scientists, and anyone interested in enhancing their understanding of probability theory and its applications in real-world scenarios.

CaptainX
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TL;DR
1. Definition
2. Properties of conditional probability
1. Definition
If E and F are two events associated with the same sample space of a random experment, the conditional probability of the event E given that F has occurred, i.e. P(E|F) is given by
P(E|F) = (E∩F)/P(F) (P≠0)

2. Properties of conditional probability
Let E and F be events of sample space S of an experiment, then we have

2.1 Property 1
P(S|F) = P(F|F) = 1
we know that
P(S|F) = P(S∩F)/P(F) = P(F)/P(F) =1
similiarly, P(F|F)= 1
P(F|F) = P(S|F) = 1

2.2 Property 2
If A and B are any two events of a sample space S and F is an event of S s.t. P(F) ≠ 0, then
P((A∪B)|F) = P(A|F) + P(B|F) -P((A∩B)|F)
In particular, if A and B are disjoint events, then
P((A∪B)|F)=P(A|F)+P(B|F)

2.3 Property 3
P(E'|F) = 1 - P(E|F)
Since S=E∪E' and E and E' are disjoint events.
 
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What is the question?
 
How to prove P(A∪B)=P(A∩B)+P(A∩B')+P(A'∩B)
 
CaptainX said:
How to prove P(A∪B)=P(A∩B)+P(A∩B')+P(A'∩B)
Try to draw a Venn diagram.
 
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