What is non/perturbative vacuum

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SUMMARY

The discussion centers on the concept of non-perturbative vacuum in quantum field theory, which is characterized by non-vanishing condensates and is essential for understanding the true vacuum state of interacting theories. Non-perturbative effects, such as those of order ##\mathcal{O}\left(e^{\frac{1}{g}}\right)##, are not captured by perturbation theory, making them crucial for accurate evaluations of the S-matrix. When spontaneous symmetry breaking occurs, the vacuum state shifts to a symmetry broken one, necessitating the use of this state for proper S-matrix calculations, as the original vacuum expectation value condition is violated.

PREREQUISITES
  • Understanding of quantum field theory principles
  • Familiarity with perturbation theory and its limitations
  • Knowledge of spontaneous symmetry breaking
  • Basic grasp of S-matrix formalism
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  • Study non-perturbative effects in quantum field theories
  • Explore the implications of spontaneous symmetry breaking on particle physics
  • Learn about the role of vacuum expectation values in quantum field theory
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This discussion is beneficial for theoretical physicists, graduate students in quantum field theory, and researchers focusing on particle physics and vacuum states.

Neitrino
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Dear PF,

I have two questions

What is non-perturbative vacuum? A state - characterized by many non-vanishing condensates? (As explained in wikipedia). In what this non-perturbativeness is manifested when there are non -vanishing condensates? So why such vacuum is calld non-perturbative?

And I was reading something where was written "In the spontaneous summetry breaking one has to use the symmetry broken vacuum when evaluating the S-matrix" My question is how/why the evaluation of S-matrix is related whether the vacuum is broken or no?

Always thank you for assistance.
 
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Neitrino said:
What is non-perturbative vacuum?
The actual vacuum of an interacting quantum field theory. Typically the vacuum we work with is the vacuum of the free theory and we approximate effects in the full theory by perturbation theory. For gauge theory this leaves many of the features of the true vacuum state outside your reach as they are nonperturbative, e.g. of order ##\mathcal{O}\left(e^{\frac{1}{g}}\right)##, and thus invisible to perturbation theory, i.e. nonperturbative.

Neitrino said:
And I was reading something where was written "In the spontaneous symmetry breaking one has to use the symmetry broken vacuum when evaluating the S-matrix" My question is how/why the evaluation of S-matrix is related whether the vacuum is broken or no?
Well if the symmetry is broken, then the actual vacuum of your theory is the symmetry broken one and particles will be excitations about this vacuum. Using the symmetric one would not be applicable.

The problem however becomes that perturbation theory in quantum field theory assumes:
$$\langle \phi \rangle = 0$$
for your fields. When the vacuum breaks the symmetry, this first condition will be violated so you have to shift to new fields. This will alter your Lagnragian to a form reexpressed in terms of fields that give rise to particles. The original Lagrangian fields, though still physically present, no longer have particle states due to breaking the vanishing vacuum expectation value condition.
 

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