What is the activation energy of the forward reaction?

Click For Summary
SUMMARY

The activation energy of a forward reaction, calculated using the Arrhenius equation, is expressed in units of J/mole. This value represents the energy required to initiate the reaction, specifically for the elementary steps involved. The enthalpy change (delta H) of the reaction is measured in J, indicating the heat absorbed or released during the reaction. The activation energy is pathway-specific and can change with the introduction of a catalyst, affecting the overall energy profile of the reaction.

PREREQUISITES
  • Understanding of the Arrhenius equation and its application in calculating activation energy.
  • Familiarity with the concept of enthalpy change (delta H) in chemical reactions.
  • Knowledge of elementary reaction steps and their significance in reaction kinetics.
  • Basic grasp of Avogadro's number and its role in converting energies from per molecule to per mole.
NEXT STEPS
  • Study the Arrhenius equation in detail, focusing on its derivation and applications.
  • Learn about the relationship between activation energy and reaction mechanisms.
  • Explore the impact of catalysts on activation energy and reaction pathways.
  • Investigate the calculation of delta H using standard heats of formation.
USEFUL FOR

Chemistry students, educators, and professionals in the field of chemical kinetics and thermodynamics will benefit from this discussion, particularly those focused on understanding reaction mechanisms and energy profiles.

FCMS34
Messages
4
Reaction score
0
In a typical General Chemistry textbook, quantitative treatments of activation energies begin with the Arrhenius equation, which is given (not derived). When R and T values are properly inserted with the given units, the activation energy comes out with the unit of J/mole.

My Question 1: Suppose that the reaction in question is mA + nB -> pC + qD (two reactants and two products). If the activation energy involved in this reaction is determined to be xJ/mole, what does it mean? xJ per mole of which substance(s)?

Typically, a schematic energy diagram accompanies such calculations, indicating an energy “mount” that represents the activation energy; and the same diagram usually indicates that the difference between the energy levels of the reactants and products is equal to the enthalpy change (delta H) of the reaction.

Delta H of a reaction always carries the unit of J (not J/mole) – this is usually found in a different chapter of a book.

My Question 2: I ran into a question that asks the following about a given reaction:
(i) What is the activation energy of the forward reaction? (This was easily calculated; the answer came out with the unit of J/mole).
(ii) What is the heat of reaction (delta H)? (This was also easily calculated from a table of standard heat of formation, by multiplying them with the number of moles, which yields a final answer bearing the unit of J (not J/mole)
(iii) What is the activation of the reverse reaction? Here, it appears that the person who made the question is expecting students to simply add the forward activation energy and delta H, but I am having difficulty with the unit (and the meaning of “per mole” which I mentioned above).

Clarification by an expert will be very much appreciated. Thank you.
 
Chemistry news on Phys.org
FCMS34 said:
In a typical General Chemistry textbook, quantitative treatments of activation energies begin with the Arrhenius equation, which is given (not derived). When R and T values are properly inserted with the given units, the activation energy comes out with the unit of J/mole.

My Question 1: Suppose that the reaction in question is mA + nB -> pC + qD (two reactants and two products). If the activation energy involved in this reaction is determined to be xJ/mole, what does it mean? xJ per mole of which substance(s)?

Typically, a schematic energy diagram accompanies such calculations, indicating an energy “mount” that represents the activation energy; and the same diagram usually indicates that the difference between the energy levels of the reactants and products is equal to the enthalpy change (delta H) of the reaction.

Activation energies make sense only when considering elementary reaction steps and not overall reaction equations. Typically elementary steps involve only a small amount of species, so we'll consider the reaction A + BC -> AB + C (similar to a SN2 reaction in organic chemistry where A reacts with BC to displace C from BC).

In this case, the activation energy represents the energy needed to break the B-C bond, offset by the energy gained from the partial A-B bond. Thus the activation energy is a property of the specific reaction, and not any particular substance in the reaction. (In fact, the activation energy is specific to the pathway the reaction takes. If, for example, you change the pathway from reactants to products by adding a catalyst, the activation energy will change.)

Delta H of a reaction always carries the unit of J (not J/mole) – this is usually found in a different chapter of a book.

My Question 2: I ran into a question that asks the following about a given reaction:
(i) What is the activation energy of the forward reaction? (This was easily calculated; the answer came out with the unit of J/mole).
(ii) What is the heat of reaction (delta H)? (This was also easily calculated from a table of standard heat of formation, by multiplying them with the number of moles, which yields a final answer bearing the unit of J (not J/mole)
(iii) What is the activation of the reverse reaction? Here, it appears that the person who made the question is expecting students to simply add the forward activation energy and delta H, but I am having difficulty with the unit (and the meaning of “per mole” which I mentioned above).

Clarification by an expert will be very much appreciated. Thank you.

Energies given in units of joules actually represent energies per molecule. For example, in the reaction A + B -> C, a ΔH of 5J would mean that 5J of heat are absorbed when one molecule of C is produced. Therefore, to convert from energies per molecule to energies per mole, all you need to do is multiply by Avogadro's number (6.02x1023 mol-1).
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 37 ·
2
Replies
37
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 131 ·
5
Replies
131
Views
10K
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K