What is the angle between the ropes in a 3-way tug of war?

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SUMMARY

In a 3-way tug of war involving Allie, Beth, and Cathy, the forces exerted are 30N, 50N, and 70N respectively. The equilibrium condition leads to the calculation of the angle between Allie's and Beth's ropes using the cosine law. The initial calculation yields an angle of 120 degrees, but the correct angle between the two ropes is 60 degrees, derived from the supplementary angle principle (180 - 120 = 60). This distinction clarifies the difference between the angle in the force triangle and the angle between the ropes.

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Allie, Beth, and Cathy are having a 3 way tug of war. Allie is pulling with a force of 30N, Beth with 50N, and Cathy with 70N. If the system is in equilibrium, what is the angle between Allie's rope and Beth's rope.

I used the cosine law, and

[tex]cos\theta=\frac{{30}^2+{50}^2-{70}^2}{2\cdot 30\cdot 50}[/tex]
[tex]\theta = 120[/tex]

But the answer is 60, because 180-120=60. Why?
 
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The angle you have calculated in the force triangle (shown by the arrow) is not the angle θ between the two ropes A and B.
forces.png
 

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