What is the area of triangle PQR divided into six smaller triangles?

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SUMMARY

Triangle PQR is divided into six smaller triangles by lines drawn from its vertices through a common interior point. The areas of four of these smaller triangles are provided, allowing for the calculation of the total area of triangle PQR. By applying the principle of area addition and the properties of triangles, the area of triangle PQR can be determined definitively based on the known areas of the smaller triangles.

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As shown in the figure below, triangle $PQR$ is divided into six smaller triangles by lines drawn from the vertices through a common interior point. The areas of four of these triangles area as indicated. Find the area of triangle $PQR$.
 

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Label the common interior point $S$, the intersection opposite $P$, $T$, opposite $Q$, $U$ and opposite $R$, $V$. Let $\triangle{PSU}$ be $x$ and $\triangle{RST}$ be $y$.$$\text{ }$$The bases of two adjacent triangles sharing a common side and having the same height are in the same ratio as the ratio of their areas, hence$$\frac34(124+x)=65+y\Rightarrow112=4y-3x$$and$$\frac12(84+x)=y\Rightarrow84=2y-x$$Solving this system of equations yields $x=56$ and $y=70$, so the area of $\triangle{PQR}$ is $315\text{ units}^2$.
 

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