What is the best deal for maximum profit?

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Discussion Overview

The discussion revolves around a mathematical model for the growth of a population of an endangered species, specifically focusing on finding the limit of the function P(t) as time t approaches infinity. Participants explore the implications of the model, its graphical representation, and the interpretation of its limit.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants present the model P(t) = (500)/[1 + 82.3e^(-0.162t)] and inquire about finding the limit as t approaches infinity.
  • There is a suggestion that the graph of P(t) could be useful for understanding the limit, with points on the graph being in the form (t, P(t)).
  • One participant notes that the function is exponentially decaying due to the negative exponent on e, leading to the conclusion that the limit is 500.
  • Another participant agrees with the conclusion that as t approaches infinity, the term 82.3e^(-0.162t) approaches zero, simplifying the expression to 500/1.
  • There is a humorous acknowledgment of correctness from one participant, indicating a light-hearted tone in the discussion.

Areas of Agreement / Disagreement

Participants generally agree on the limit of the function being 500 as t approaches infinity, though the discussion includes multiple reiterations of the model and its implications. Some posts appear to be repetitive or off-topic, which may indicate a lack of focus on the main mathematical inquiry.

Contextual Notes

Some posts lack detail or clarity, and there are references to additional problems and screenshots that are not provided in the thread. The discussion also includes informal remarks that may detract from the technical focus.

Who May Find This Useful

Readers interested in mathematical modeling, population dynamics, or limit calculations in calculus may find this discussion relevant.

nycmathdad
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The model below is given to find the growth of a population of an endangered species.

P(t) = (500)/[1 + 82.3e^(-0.162t)]

Find the limit of P(t) as t tends to positive infinity.

The answer in the textbook is 500.

Can a model like this be graphed? If so, is the graph of P(t) the best approach to find the limit?
Points on the graph of P(t) are in the form (t, P(t)). Correct?
 
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Beer soaked ramblings follow.
nycmathdad said:
The model below is given to find the growth of a population of an endangered species.

P(t) = (500)/[1 + 82.3e^(-0.162t)]

Find the limit of P(t) as t tends to positive infinity.

The answer in the textbook is 500.

Can a model like this be graphed? If so, is the graph of P(t) the best approach to find the limit?
Points on the graph of P(t) are in the form (t, P(t)). Correct?
Problem 1.5.79.a.
Again, you left out a lot of details.
A screenshot will be helpful.
The problem is asking you to find $\lim_{t \to \infty} P(t)$
 
I am interested in 79 partn(a) only.

Here it is:

Screenshot_20210402-185104_Drive.jpg
 
nycmathdad said:
The model below is given to find the growth of a population of an endangered species.

P(t) = (500)/[1 + 82.3e^(-0.162t)]

Find the limit of P(t) as t tends to positive infinity.

The answer in the textbook is 500.

Can a model like this be graphed? If so, is the graph of P(t) the best approach to find the limit?
Points on the graph of P(t) are in the form (t, P(t)). Correct?

It's an exponentially decaying function due to the negative power on e. So what value do you think that the exponential function tends to?
 
Prove It said:
It's an exponentially decaying function due to the negative power on e. So what value do you think that the exponential function tends to?

Well, 82.3e^(-0.162t)] becomes zero leaving the expressing 500/1. The limit is 500.
 
nycmathdad said:
Well, 82.3e^(-0.162t)] becomes zero leaving the expressing 500/1. The limit is 500.

Correct.
 
Prove It said:
Correct.

Me correct? Really? Wow!
 
Beer soaked non sequitur ramblings follow.
nycmathdad said:
Me ...
The best deal is the one that brings the most profit.
 

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